Why Tungsten Alloy Radiation Shielding is Better than Other material?
Views : 947
Update time : 2016-09-29 11:56:12
When designing radiation shielding, it will be calculated according to thickness of shielding material to get total weakened multiple for layers of shield.
Formula: T(1/2) = e0.693 d /K (A)
K: Shield weakened multiple,it is a constants
T(1/2): The nuclear radiation shielding material of the half-value layer values.
d: Shielding thickness.
T(1/2) is more small more better, means the radiation shielding more effect.
According to this formula, e0.693 and K is a confirmed constants,so the only factor influence the T(1/2) is d, that is shielding thickness.
Let's take 1 units of area as sample to explain, how the material density influence the thickness,therefor enfluence the shielding effective.
We all know, formula: V=M/P (B).
V: Volume
M: weight
P:density
in the Cuboid shape things.
V= S*d (C)
V:Volume
S:basal area
d: thinkness
Combine formula B and C, S*d=M/P. That is d=M/P/S. (D)
conbine formula A and D. we can get:
T(1/2) = e0.693 *M/P/S/K
In this formula. e0.693, S, K are already confirmed. so the nuclear radiation shielding material of the half-value layer values, is influence by P.
the P is more bigger, the T(1/2) is more small, therefor the material radiation shielding effective is more better.
In this way, tungsten alloy material has a density over 18g/cm3, 60% higher than lead and Al2O3, is a better radiation shielding material than them.
If you are going to purchase some tungsten alloy radiation sheilding part,try to click here or contact Ms Enjoy.
http://www.ejtungsten.com/c/shielding-parts_0008
Formula: T(1/2) = e0.693 d /K (A)
K: Shield weakened multiple,it is a constants
T(1/2): The nuclear radiation shielding material of the half-value layer values.
d: Shielding thickness.
T(1/2) is more small more better, means the radiation shielding more effect.
According to this formula, e0.693 and K is a confirmed constants,so the only factor influence the T(1/2) is d, that is shielding thickness.
Let's take 1 units of area as sample to explain, how the material density influence the thickness,therefor enfluence the shielding effective.
We all know, formula: V=M/P (B).
V: Volume
M: weight
P:density
in the Cuboid shape things.
V= S*d (C)
V:Volume
S:basal area
d: thinkness
Combine formula B and C, S*d=M/P. That is d=M/P/S. (D)
conbine formula A and D. we can get:
T(1/2) = e0.693 *M/P/S/K
In this formula. e0.693, S, K are already confirmed. so the nuclear radiation shielding material of the half-value layer values, is influence by P.
the P is more bigger, the T(1/2) is more small, therefor the material radiation shielding effective is more better.
In this way, tungsten alloy material has a density over 18g/cm3, 60% higher than lead and Al2O3, is a better radiation shielding material than them.
If you are going to purchase some tungsten alloy radiation sheilding part,try to click here or contact Ms Enjoy.
http://www.ejtungsten.com/c/shielding-parts_0008